Question

An alarm clock is set to ring for a total of 1.00 minute. It is placed on a spaceship moving at 0.6 c. According to Mission Control on Earth, the alarm clock rings for:

A) 0.60 min

B) 0.64 min

C) 0.80 min

D) 1.00 min

E) 1.25 min

Answer 1

@uri

Answer 2

@agent0smith

Answer 3

@helpkay @jabez177

Answer 4

i'm sorry i have no idea try putting it in the math section

Answer 5

LOL its a physics question thou?

Answer 6

@mrm

Answer 7

@MarcoReus11

Answer 8

@mathmale

Answer 9

@Mehek14

Answer 10

@Qwertty123 @rishavraj

Answer 11

@T-Dawg02 @UliNK

Answer 12

Use time dialation formula

Answer 13

U hv to find out
t=?

Answer 14

Given
t not
V

Answer 15

oh ok are we solving for t or v?

Answer 16

speed is not given v?

Answer 17

https://www.google.ca/search?q=time+dilation+formula&biw=1366&bih=667&source=lnms&tbm=isch&sa=X&sqi=2&ved=0ahUKEwj7n73OsPHMAhVq6oMKHUD-DY8Q_AUIBigB#imgrc=qzgnXbEyjoyy2M%3A

are we using this formula?

Answer 18

Given
V=0.6c

Answer 19

and t=1.00 m

Answer 20

no

Answer 21

\[t _{0}=1\min\]

Answer 22

i like to write the equation as
\[t=\frac{ t _{0} }{ \sqrt{1-\frac{ v ^{2} }{ c ^{2} }} }\]

Answer 23

tell me t=?

Answer 24

use
\[t _{0}=1 \min\]

Answer 25

\[v=0.6c\]

Answer 26

\[v/c=0.6\]

Answer 27

c= 3.0x10^8?

Answer 28

plank's constant?

Answer 29

i will be back

Answer 30

u can
\[t=\frac{ 1 }{ \sqrt{1-\frac{ v ^{2} }{ c ^{2} }} }=\frac{ 1 }{ \sqrt{1-0.6^{2}} }=?\]

Answer 31

there is no planks constant here

Answer 32

i got 1.25

Answer 33

thanks bro

Answer 34

why v/c=0.6?