PLEASE HELP!
the equation of line AB is y=-1/3-1. Write an equation of a line perpendicular to line AB in slope-intercept form that contains point (4,-5)
Perpendicular slope = Negative reciprocal
So negative of -1/3 = 1/3 reciprocal is 1/3 = 3/1 = 3 so the slope is 3 Now we need the rest of the equation y = 3x + b Plug the ordered pair -5 = 3 * 4 + b Can you solve for b?
-5=12+b move the 12 7=b ?
-5 = 12 + b Subtract 12 -5 - 12 = b
Oh whoops I did that wrong So it's -17?
I'm sorry I'm terribly bad at math in general
is that correct?
Lol it's alright ^_^ Yes - 17 so b = -17 Now we have the whole line y = 3x - 17
That's what I would put as the equation?
Yes :)
Thank you!(:
Can I borrow you for one more question?
Can you wait a few mins? o.o Gotta do something quick :P
I sure can (: I'll make a new question and tag you (:
Alright ^_^
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