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HELP! PLEASE! Find length x in the triangle
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|dw:1464141836269:dw|
|dw:1464141265718:dw|
would the third angle be 32?
correct.
how would i know the opposite and hypotenuse ?
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|dw:1464141467005:dw|
A,B,C are angles. a,b,c are sides of triangle.
but i only know one side...
\[\frac{ 120 }{ \sin 32 }=\frac{ x }{ \sin 53 }\]
would i do the following : (120)(sin 53) and (x)(sin32)
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find x
you have to take angle opposite to side.
would it be 180?
\[x=120*\frac{ \sin 53 }{ \sin 32 }=120 \times \frac{ 0.80 }{ 0.53 }=181\] it is nearly 181
thank you @sshayer
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yw
as you know third angle ,you can also find third side .
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