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OpenStudy (samirahdanyel):
jhonyy9 (jhonyy9):
do you understand this options what mean ?
OpenStudy (samirahdanyel):
no i dont
jhonyy9 (jhonyy9):
|dw:1464404338245:dw|
OpenStudy (samirahdanyel):
so what do you have to solve for?
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OpenStudy (samirahdanyel):
i got the first answer
jhonyy9 (jhonyy9):
so than you read the 3rd option what say i agree with this that in this case the quadrilateral not can being parallelogram - your opinion ?
OpenStudy (samirahdanyel):
i mean that could be true too
OpenStudy (samirahdanyel):
i think that one is true
jhonyy9 (jhonyy9):
but read please there on the top what is the question ?
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OpenStudy (samirahdanyel):
yes i read it
OpenStudy (samirahdanyel):
the unknown angle measures 70 degrees
jhonyy9 (jhonyy9):
so than you check these angles with given measure of this x value so you see that how wrote there for x=35 result 3 angles with degree equal 70 and in this case the 4 th angles need being with 150 degree bc. 3*70=210 and you know that the sum of angles of a quadrilateral is equal 360 degree - yes ?
OpenStudy (samirahdanyel):
okay now I understand
jhonyy9 (jhonyy9):
not can being the 70 degree bc. the sum than not will give never 360 degree
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OpenStudy (samirahdanyel):
oh okay I see now
jhonyy9 (jhonyy9):
so and what is the right answer ?
OpenStudy (samirahdanyel):
OpenStudy (samirahdanyel):
@jhonyy9
jhonyy9 (jhonyy9):
yes - but you not said me what is the right answer to the past exercise
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OpenStudy (samirahdanyel):
thats the answer to the past exercise
jhonyy9 (jhonyy9):
where is and what ?
jhonyy9 (jhonyy9):
ok. i got it now - good job
hopw that is clearly for you sure