A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ .
Just need a check i think sqrt13

5
√(13)
√(97)

Question

A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ .
Just need a check i think sqrt13

5
√(13)
√(97)

jim_thompson5910 · Answer

one moment. I'm using geogebra to check

jim_thompson5910 · Answer

http://prntscr.com/b9bwez the green segment f is the shorter diagonal f = 3.61 approx f^2 = 13.0321 approx turns out that f^2 is exactly equal to 13 if there's no rounding error so f = sqrt(13) exactly which means you have the correct answer. Nice job

tori1423 · Answer

thxs

jim_thompson5910 · Answer

no problem