Question

help?

Answer 1

@jhonyy9

Answer 2

tan theta = ?

cot theta = ?

rewrite that in function of sin and cos please

Answer 3

please collaborate bc. the rule of OS dont like giving direct right answers - hope you know it

Answer 4

Tan theta =1

Answer 5

no

in function using sin and cos

tan theta = (sin theta)/(cos theta)

so cot theta = ? this you need rwrite it

Answer 6

tan(theta) = sin(theta) / cos(theta)
and
cot(theta) = 1/ tan(theta)

Answer 7

yes this is true but rewrite the cot theta same with tan theta using sin and cos please

Answer 8

Im not too sure how to do that... sooo.

Answer 9

cot theta = 1/tan theta = 1/(sin theta/costheta) = ?

Answer 10

you dont know it ?

Answer 11

= cos /sin

Answer 12

yes ?

Answer 13

sin theta cos theta

Answer 14

Oh okay.. so no theta?

Answer 15

yes theta just shorted it

so

tan theta = sin theta / cos theta

cot theta = cos theta / sin theta

sin theta cos theta
-------- + --------- =
cos theta sin theta

do you can continue it ?

Answer 16

Sin theta/cos theta

Answer 17

no

you need assuming these fractions

Answer 18

with common denoinator and ... so much

Answer 19

denominator

Answer 20

do you can ?

Answer 21

tan theta+cot theta

Answer 22

yes from this started you need getting what there is on the right side

Answer 23

What did you just say?

Answer 24

do you can assuming these fractions ?

Answer 25

No I got it right.. didnt I?

Answer 26

not is right again

sin cos sin^2 +cos^2 1
--- + ---- = ------------- = ---------
cos sin sin*cos sin *cos


sorry i not have wrote there on every places the theta but please consider that are there

so the result is that


tan + cot = 1/(sin cos

Answer 27

hope you understand it clearly sure

Answer 28

YES! thank you! I appreciate it! I honestly do.. I knwo because my head hurts.. lol

Answer 29

np

was my pleasure

bye bye