Question

help?

Answer 1

@sshayer

Answer 2

HI!!

Answer 3

Hey girl!

Answer 4

from \(12\) to \(52\) is a variation of \(52-12=40\) so you will want to make the amplitude of your function half of that, namely 20

Answer 5

from 9:15 to 3:30 is \(6\tfrac{1}{4}\) hours , so that is half your period

Answer 6

making the period \(12.5\) hours (from low tide to low tide)

Answer 7

function will look like \[f(x)=-20\cos(bx)\] to find \(b\) solve \[\frac{2\pi}{b}=12.5\] for \(b\)

Answer 8

the minus sign because when you start, it is LOW tide

Answer 9

oh also you have to add \(32\) out at the end to make it \(12\) when you start at \(52\) at high tide

Answer 10

\[f(x)=-20\cos(bx)+32\]

Answer 11

can you find \(b\)?

Answer 12

Hey sorry my internet went out for a moment there. thanks so much. I think I can manage ill let you know what I get!

Answer 13

I got pi over 6.25! Thanks so much!