Question

Can someone please help me with this math question?
Please? I will fan and give a medal!!
Please help me to simplify this rational expression -
x^2-1 x-1
-------- / -----
2x 4x^2
**Note the / means to divide

Answer 1

\[\frac{x^2-1}{2x}\times \frac{4x^2}{x-1}\] is a start
then factor and cancel

Answer 2

Could you show me how to do that ?

Answer 3

\[x^2-1=(x+1)(x-1)\] i guess is the only thing you can factor
more cancels though

Answer 4

\[\frac{(x+1)(x-1)}{2x}\times \frac{4x^2}{x-1}\]

Answer 5

the \(x-1\) cancels top and bottom
as does the \(\frac{4x^2}{2x}\) which becomes \(2x\)in the numerator

Answer 6

Thank you for the help!!! I really appreciate it!!