Question

WILL FAN AND MEDAL PLEASE HELP!!!!!!!!!!!!!!! QUICK!!!!!!!

Find the quotient of quantity of 6 times x to the 3rd power minus 18 times x to the 2nd power minus 12 times x all over negative 6 times x.

−x2 − 3x − 2
x2 − 18x − 12
−x2 + 18x − 12
−x2 + 3x + 2

Answer 1

Will fan and medal please help

Answer 2

@.Sam.

Answer 3

@jigglypuff314

Answer 4

@jigglypuff314

Answer 5

@.Sam.

Answer 6

okay first we write the given information in mathematical terms-

we have this-> Find the quotient of quantity of 6 times x to the 3rd power minus 18 times x to the 2nd power minus 12 times x all over negative 6 times x.

\(\Large \frac{6 \times x^3-18 \times x^2-12 \times x}{-6 \times x}\)

can you simplify it from here? =]

Answer 7

dont you switch everything to the other row if it is negative?

Answer 8

yes true

we can also cancel out the common terms from the numerator and the denominator

Answer 9

ok so it would be B?

Answer 10

umm nope

we can start like this-

\(\Large \frac{6 \times x^3-18 \times x^2-12 \times x}{-6 \times x}\)

\(\Large \frac{6x(1x^2-3x-2)}{-6x}\)

here we cancel out 6x from numerator and denominator to get this-

\(\Large (-x^2+3x+2)\)

Answer 11

oh ok, i understand now

Answer 12

okay =]

Answer 13

thank you

Answer 14

np