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Can someone give me a refresher on this? Let π(π₯) = 4π₯ + 1 πππ π(π₯) = 2π₯ 2 β 3 . Find (π β π)(π₯)
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(f-g)(x) just means subtract f(x) - g(x)
a) β2π₯^2 + 4π₯ + 4 b) β2π₯^2 + 4π₯ β 4 c) 2π₯^2 β 4π₯ + 2 d) 2π₯^2 β 4π₯ + 4
so it ends up being 4x + 1 - 2x^2 + 3
combine like terms
β2π₯^2 + 4π₯ + 4 correct?
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very good
Thanks so much, @Vocaloid
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