I agree with @RedoHawk. Each die will have 6 on it, add them together to get 12. Each die only has four appearing once. So, 2 instances, 12 total outcomes. 2/12 = 1/6.
OpenStudy (help!!!!):
uhmm. I'm pretty sure that there are 10 outcomes where there is one 4 for each pair
OpenStudy (help!!!!):
so |dw:1464907406224:dw|
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OpenStudy (mathmate):
|dw:1464907413713:dw|
Total outcomes: 36
Exactly one 4, count the X =10/36
At least one 4 count the X and the O = 11/36
Both are 4, count the O = 1/36
It depends on the interpretation of the question.