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OpenStudy (help!!!!):
Question: How many 5-card hands having exactly 3 aces and 2 other cards can be dealt?
OpenStudy (help!!!!):
Answer: 4C3=4 48C2=1128 4*1128=4512
OpenStudy (help!!!!):
Why is it "4c3"? @jim_thompson5910 @mathmate
OpenStudy (help!!!!):
Oh.. nvm
OpenStudy (help!!!!):
I got it..
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jimthompson5910 (jim_thompson5910):
There are 4C3 ways to draw 3 aces There are 48C2 ways to draw the other two cards
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