Question

@Vocaloid

Answer 1

\[\frac{ y+5 }{ y^2 +4y-32 }\]

Answer 2

i was thinking of y = 5 and 32

Answer 3

not quite

try factoring the denominator first

Answer 4

Okay \[(y-4)\] and \[(y+8)\]?

Answer 5

very good

now, break it into its two factors and set each factor equal to 0

y - 4 = 0
y + 8 = 0

and solve for y

Answer 6

(you will get 2 values)

Answer 7

Oh i think i got it, \[y=4 , y=-8\]

Answer 8

great!

Answer 9

for excluded values, the numerator usually doesn't have any affect