Question

What is the perimeter of the figure outlined by the
solid line, in terms of x?

http://imgur.com/nbX8WZF

Answer 1

hint:
first step
the radius of the circle, is:
\(r=(6x)/2=3x\)
so the perimeter of the half circle, is:
\[\frac{{2\pi \left( {3x} \right)}}{2} = ...?\]
please simplify

Answer 2

@Michele_Laino Yes I got that far. pi * 3x

Answer 3

hey adam,
here ,
radius of semicircle = 6x/2=3x
now, in any of the two right triangles,
height = 4x , base= 3x
hence, \[(3x)^2 + (4x)^2 = (hypotenuse)^2 \]
(Pythagoras theorem)
THus, hypotenuse = 5x
also perimeter of semicircle = pi*3x
thus, req perimeter = 5x +5x+ 3pi*x
=10x +3pi*x
please medal.....