Question

I need help ;-; pls help me I have some parts done

Complete the equation of the graphed linear function. Write the slope in decimal form.

http://prntscr.com/bcetwd

Answer 1

Choose 2 points from the line

Btw the y-intercept is incorrect

Answer 2

oh dang

Answer 3

k give me a sec

Answer 4

but the line has to be touching the intercepts ;-;
I see only -4 touching the line

Answer 5

You can pick any 2 points from the line, not just intercepts

Answer 6

ok

Answer 7

2-(-3)/ 5 - 1 ? idk
i tried ;-;

Answer 8

Can you tell me the 2 points first

Answer 9

2, 3

Answer 10

-3* my bad

Answer 11

(2, -3) is not on the line

Answer 12

oh no i took two different points

Answer 13

You need from the line to find the slope

Answer 14

i thought you said dont pick intercepts

Answer 15

ANY point from the line works

Answer 16

that's what i did though

Answer 17

You chose that was not on the line

Answer 18

Nvm here let me tell you,
you see (0,-4) it's on the line
you see (-4,-1) the line passes trough that as well

Answer 19

Now we use the slope formula

\(\dfrac{-1--4}{-4-0}\)

Answer 20

Well yes, -4 was one of my original things I was going to put, but once you said it can't be intercepts, I guess I got confused.

Answer 21

I never said you couldn't

Answer 22

Oh wait...your right x'D

Answer 23

"You can pick any 2 points from the line, not just intercepts"

Meaning it doesn't have to be only intercepts

Answer 24

I realize that now.

But how'd you get -1

Answer 25

I chose the ordered pair (-4,-1) because it's from the line?

Answer 26

oooooh ok

Answer 27

so -1 - (-4)= 3
----
and -4 - 0 = 4 ?

Answer 28

http://prntscr.com/bceyod

Which I'm trying to tell you that it has to be from the line, not just anywhere from the graph

Answer 29

ok I get it

Answer 30

-4 - 0 = -4

Answer 31

so the slope is

-3/4

Answer 32

y = `-3/4`x + `___`

now we need y-intercept

Answer 33

-4

Answer 34

?

Answer 35

yes

Answer 36

so y = `-3/4` x + `-4`

Answer 37

:O oh dang....tysm!!!!

Answer 38

You're welcome :)