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PLEASE HELP WILL GIVE MEDAL Choose the correct simplification of the expression 4 over y to the power of negative 3. A 4y3 B 4 over y to the 3rd power C y to the 3rd power over 4 D This expression is already simplified.
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\[\large x^{-a} = \frac{1}{x^a}\] or the inverse is \(\huge \frac{1}{x^{-a}}\) = \(\huge x^a\) `4 over y to the power of negative 3` 1) There is a fraction, where 4 is the numerator and \(y^{-3}\) is in the denominator. \(\large \frac{4}{y^{-3}}\). Since a negative power is raised, it will be put to the numerator, where it would become: \(\large \frac{4y^3}{1}\) or \(\large 4y^3\)
so it is A
Yes
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