Question

let f(x) = x^2+48x+2000

find f'(x)
determine the slope of the tangent line at x=0

Answer 1

@Photon336

Answer 2

okay so find the slope at x = 0

Answer 3

\[\frac{ d }{ dx }(x^{2}+48x+2000) = 2x+48 \]

Answer 4

\[|_{x=0}(2x+48) = 48 \]

Answer 5

@marcelie

Answer 6

yup looks good :p