Question

Find the value of 42^3 using the identity (x + y)^3 = x^3 + 3x^2y + 3xy^2 + y^3.

Hint: 42^3 = (40 + 2)^3; therefore, x = 40 and y = 2.

Answer 1

please help

Answer 2

What's stopping you from using the given hint ?

Answer 3

im trying it the with hint now actually

Answer 4

Good
Let me know how you're doing

Answer 5

64,000+3(1600)2+3(40) 4+ 8
i substituted x and y the numbers and solved them

Answer 6

Excellent
Try simplifying

Answer 7

can you go through that with me step by step?

Answer 8

64,000+3(1600)2+3(40) 4+ 8
64000+4800⋅2+3(40)⋅4+8
64000+9600+3(40)⋅4+8
64000+9600+120⋅4+8
64000+9600+480+8
73600+480+8
74080+8
74088
@ganeshie8