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Find the range of the function: F(x)=(x-2)^2+2
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range lowest y values to highest y values
aah this is tricky hmm im thinking that it might be (2 , infinity )
\[\left( x-2 \right)^2\ge0\] \[\left( x-2 \right)^2+2 \geq0+2\] \[\left( x+2 \right)^2+2 \geq 2\]
correction it is (x-2)^2
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