Question

Errg how do I solve for T here?

Answer 1

\[\frac{ T-m_1 g }{ m_1 }=\frac{ -T+m_2 g }{ m_2 }\]

Answer 2

nvm I figured it out hehe

Answer 3

solve for T

\[m_{1}m_{2}*\frac{ T-m_{1}g }{ m_{1} } = \frac{ -T+m_{2}g }{ m_{2} }*(m_{1}m_{2})\]

\[m_{2}( T-m_{1}g ) = (-T+m_{2}g) m_{1}\]

\[m_{2}T-m_{1}m_{2}g = -Tm_{1}+m_{2}m_{1}g\]

\[m_{2}T+Tm_{1} = 2(m_{2}m_{1}g)\]

\[T(m_{2}+m_{1}) = 2(m_{1}m_{2}g)\]

\[T = \frac{ 2(m_{2}m_{1}g) }{ (m_{1}+m_{2}) }\]