Question

d

Answer 1

@Michele_Laino

Answer 2

@pooja195

Answer 3

do you mean:
\[\cot 90 = \frac{{\cos 90}}{{\sin 90}} = ...?\]

Answer 4

i guess....😩

Answer 5

hint:
\[\cot 90 = \frac{{\cos 90}}{{\sin 90}} = \frac{0}{1} = ...?\]

Answer 6

o

Answer 7

yes!

Answer 8

wha bout scs n sec??

Answer 9

we have the subsequent \(definitions\):
\[\large \begin{gathered}
\sec \alpha \equiv \frac{1}{{\cos \alpha }} \hfill \\
\hfill \\
\csc \alpha \equiv \frac{1}{{\sin \alpha }} \hfill \\
\end{gathered} \]

Answer 10

oki

Answer 11

:)

Answer 12

thanks einstein❤❤❤💘💘💍

Answer 13

lol :) :)
thanks! :)