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Mathematics 18 Online
OpenStudy (seb.cal):

The grades on the last art exam had a mean of 75%. Assume the population of grades on art exams is known to be distributed normally, with a standard deviation of 7%. Approximately what percent of students earn a score between 75% and 82%? A. 37.2% B. 84.1% C. 34.1% D. 50%

OpenStudy (seb.cal):

I know the answer is 34.1%, but I don't understand how to get to that conclusion.

OpenStudy (leenathan):

do you have a calculater?

OpenStudy (seb.cal):

Yes.

OpenStudy (seb.cal):

@zepdrix @.Sam. @Whitemonsterbunny17 Please help?

OpenStudy (seb.cal):

@uri @Vocaloid Help explain?

Vocaloid (vocaloid):

are you familiar with the 68-95-97 rule?

OpenStudy (seb.cal):

Sounds familiar... But no. I can't recall.

Vocaloid (vocaloid):

it's a rule for normal distributions (like the one above) it tells us what percentage of data should fall between what values, depending on standard deviation

Vocaloid (vocaloid):

it works like this

Vocaloid (vocaloid):

|dw:1465417094737:dw|

OpenStudy (seb.cal):

Ok! I've seen that in my lessons.

Vocaloid (vocaloid):

|dw:1465417105604:dw|

Vocaloid (vocaloid):

|dw:1465417130368:dw|

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