Mathematics
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OpenStudy (aprilrm21):
PRECALC HELP PLEASE!!!
Verify: csc^2xcot^2x + csc^2x = csc^4x
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OpenStudy (aprilrm21):
@TheSmartOne
OpenStudy (welshfella):
i think we can use the identity
csx^2 x = 1 + cot^2 x
OpenStudy (welshfella):
from this cot^2 x = csc^2 x - 1
plug this into the left side of the identity and simplify.
OpenStudy (aprilrm21):
So change all the csc to 1+cot^2x ?
OpenStudy (welshfella):
No change the cot^2 x to csc^2 x - 1
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OpenStudy (aprilrm21):
So then would the exponents multiply in in the first part?
OpenStudy (welshfella):
so
csc^2 x ( csc^2 x - 1) + csc^2 x
Simplify this and see what you get.
OpenStudy (welshfella):
when you multiply you add exponents
OpenStudy (welshfella):
its now easy to solve.
OpenStudy (aprilrm21):
So right now I have csc^4x - 1 + csc^2x
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OpenStudy (aprilrm21):
Am I on the right track?
OpenStudy (welshfella):
you made 1 mistake
csc^2 x is distributed over every term in the parentheses.
OpenStudy (aprilrm21):
OH! So the last 2 terms cancle!
OpenStudy (welshfella):
you did csc^2 x + csc^2 x = csc^4 x
but also its csc^2 x * -1
OpenStudy (welshfella):
yes they cancel leaving just csc^4 x
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OpenStudy (aprilrm21):
Thank you so much!
OpenStudy (welshfella):
yw