Question

find integral

Answer 1

\[\int\limits 18x^2(x^3-7)^{3/2}dx\]

Answer 2

find u first

Answer 3

try the substitution u = (x^3 - 7)

Answer 4

Correct.
\[du=3x^2\]

Answer 5

yes but i dont know what 18x^2 dx is how do i find that?

Answer 6

du= 3x^2

Answer 7

\[6\int\limits_{}^{}(u)^{3/2}\]