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Mathematics 13 Online
OpenStudy (amtran_bus):

At a convention of monsters, 2/5 have no horns, 1/7 have one horn, and 1/3 have two horns, and the remaining 26 have three or more horns. How many monsters are attending the convention?

OpenStudy (amtran_bus):

I know that if I found a common denominator for the 3 fractions it is 92/105.

OpenStudy (amtran_bus):

ohhh I need 105/105 so there are 13/105 left!

OpenStudy (amtran_bus):

13/105 m = 26

ganeshie8 (ganeshie8):

Looks you have it !

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