A 20g mass suspended from metre rod at 15cm mark while the rod is pivoted at 40cm mark weight of the rod will be
1) 50N
2) 0.5N
3) 5N

Question

A 20g mass suspended from metre rod at 15cm mark while the rod is pivoted at 40cm mark  weight of the rod will be 
1) 50N 
2) 0.5N 
3) 5N

shikamaru11 · Answer

@Preetha

shikamaru11 · Answer

@agent0smith

shikamaru11 · Answer

O.o Is there anyone who can help me out

agent0smith · Answer

Draw a diagram

shikamaru11 · Answer

|dw:1465586549537:dw| 
wight of the rod is at the centre

agent0smith · Answer

Weight times distance from pivot for the left = weight times distance from pivot for the right

shikamaru11 · Answer

2 * 0.25 = 0.5N O.o after that step i can't understand

agent0smith · Answer

I don't have a clue what you are doing with those numbers.

Find the weight on the left using W=mg. How far is the weigh on the left from the pivot? 

How far is the centre of mass of the rod from the pivot?

weight*distance from pivot [on left] = weight*distance from pivot [on right]

shikamaru11 · Answer

well i know and you're rite but these're the only numbers I'd that's why I asked

agent0smith · Answer

Use units, make things clear as to what you are doing. But first see my above post.

shikamaru11 · Answer

okay got it

agent0smith · Answer

Okay, so...