Question

help please number 7

http://prntscr.com/bfp32i

Answer 1

https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8#q=y%3D(x-2)%5E2%2C%20y%3Dx

Answer 2

how would you set up the equation ?

Answer 3

@mayankdevnani help her

Answer 4

y=(x-2)^2
y=x
(x-2)^2=x
x^2-4x+4=x
x^2-4x-x+4=0
x(x-4)-1(x-4)=0
(x-4)(x-1)=0
x=1,4

Answer 5

\[reqd.~area=\int\limits_{1}^{4}\left[ x-\left( x-2 \right)^2 \right]dx=\int\limits_{1}^{4}\left( x-x^2+4x-4 \right)dx=?\]