Can you check my answer? fan+medal
Rita's company reimburses her expenses on food, lodging, and conveyance during business trips. The company pays $55 a day for food and lodging and $0.45 for each mile traveled. Rita drove 300 miles and was reimbursed $2,335. Part A: Create an equation that will determine the number of days x on the trip. Part B: Solve this equation justifying each step with an algebraic property of equality. Part C: How many days did Rita spend on this trip?
Part A: 55x + 0.45(300) = 2335 Part B: 55x + 0.45(300) = 2335 55x + 135 = 2335 55x + 135 - 135 = 2335 - 135 55x = 2200 55x/55 = 2200/55 Part C: x = 40
@Preetha @zepdrix
@jhonyy9
@MAGENTAMA202
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omg someone tagged me
just one sec i'll help u out
ok so for part A, your equation is almost correct... you just want to have the variable "y" in for the miles since you dont need to solve it yet - thats the next step. The equation should look like this: 55x + 0.45y = 2335
ok
what about the 300 miles
And part B is perfect - nice work!
the 300 for the miles (300=y) is correct as well. You may want to write 300=y next to the equation at the beginning of Part B.
For part C, just mention something like x=days on the trip=40. Otherwise, perfect as well.
do you have any other questions?
what about the proporties
so for that it just means like what property you used... you can go to this link for the properties: http://hotmath.com/hotmath_help/topics/properties-of-equality.html
From 55 x + 0.45 (300) = 2335 I got x = 40 days
@robtobey2 can you help 11study11 with the properties? I gave a link although am not quite sure what would go for each step. But what it seems her(?) teacher is requesting is for a different property of equality for each step.
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