Question

PLease help:))

Answer 1

@jim_thompson5910 could you help me when you can :)

Answer 2

http://www.glencoe.com/sec/math/algebra/algebra2/algebra2_05/extra_examples/chapter10/lesson10_4.pdf
see page 1, example 2


The formula we'll use is
\[\Large \log(E) = 11.8 + 1.5M\]
E is the energy in ergs
M is the magnitude


In this case
E = unknown
M = 2.3
solve for E
\[\Large \log(E) = 11.8 + 1.5M\]
\[\Large \log(E) = 11.8 + 1.5*2.3\]
\[\Large \log(E) = 11.8 + 3.45\]
\[\Large \log(E) = 15.25\]
\[\Large E = 10^{15.25}\]
\[\Large E = 1.778\times10^{15}\]

Answer 3

thank you!

Answer 4

no problem