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Mathematics 18 Online
OpenStudy (samirahdanyel):

Can someone help me? attachment below

OpenStudy (samirahdanyel):

OpenStudy (triciaal):

CDA = 1/2 CMA CMA = 90 therefore CDA = 90/2 = 45 ACD = CAD 180 = ACD + CAD + CDA 180 = 2 (acd) + 45 solve for ACD

OpenStudy (samirahdanyel):

so its gonna be\[180=2x+45\]

OpenStudy (triciaal):

yes : solve for x

OpenStudy (samirahdanyel):

i got 67.5

OpenStudy (triciaal):

so did I

OpenStudy (samirahdanyel):

cool thank you. Can you help me with some more questions

OpenStudy (triciaal):

another way of looking at it BD is a bisector 45/2 = 22.5 22.5 + 45 = 67.5 MCD + ACM

OpenStudy (triciaal):

open another post

OpenStudy (samirahdanyel):

okay

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