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Can someone help me? attachment below
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CDA = 1/2 CMA CMA = 90 therefore CDA = 90/2 = 45 ACD = CAD 180 = ACD + CAD + CDA 180 = 2 (acd) + 45 solve for ACD
so its gonna be\[180=2x+45\]
yes : solve for x
i got 67.5
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so did I
cool thank you. Can you help me with some more questions
another way of looking at it BD is a bisector 45/2 = 22.5 22.5 + 45 = 67.5 MCD + ACM
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okay
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