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Mathematics 4 Online
OpenStudy (mathmusician):

My last math question of the year, Calculus optimization. Help Please!!

OpenStudy (mathmusician):

@agent0smith can you help with one last question #12 please

OpenStudy (agent0smith):

Set the given equations equal to each other

OpenStudy (mathmusician):

okay

OpenStudy (mathmusician):

\[Me ^{rt}=Ce ^{k \sqrt{t}}\]

OpenStudy (mathmusician):

Do I solve for t again?

OpenStudy (agent0smith):

"how much money M"

OpenStudy (mathmusician):

so solve for m!

OpenStudy (mathmusician):

okay do i use the given values from previous problems or just keep all of the variables in it

OpenStudy (agent0smith):

They don't say. So... variables.

OpenStudy (mathmusician):

okay

OpenStudy (mathmusician):

\[M=Ce ^{\sqrt{t}k-tr}\]

OpenStudy (agent0smith):

Yep

OpenStudy (mathmusician):

and that is what i am supposed to compare to topt?

OpenStudy (agent0smith):

Same steps as before, derivative, set to 0 etc

OpenStudy (mathmusician):

okay

OpenStudy (mathmusician):

I cant derive this, ive been trying

OpenStudy (agent0smith):

If you can derive the one from a while ago, you can do this one.

OpenStudy (mathmusician):

Okay so the derivative of e^f(x) is f'(x)e^f(x)?

OpenStudy (agent0smith):

Yep, use that

OpenStudy (mathmusician):

okay

OpenStudy (mathmusician):

\[Ce ^{k \sqrt{t}-tr}(\frac{ k }{ 2\sqrt{t} }-r)\]

OpenStudy (mathmusician):

And now set equal to zero and solve for t?

OpenStudy (mathmusician):

Ill do that

OpenStudy (agent0smith):

Looks familiar, huh?

OpenStudy (mathmusician):

yeah it does

OpenStudy (mathmusician):

is it the same as topt?

OpenStudy (mathmusician):

@agent0smith

OpenStudy (agent0smith):

Yeah when I said it looks familiar, i meant cos it looks exactly the same!

OpenStudy (mathmusician):

yeah haha thanks mate!

OpenStudy (agent0smith):

Welcome mate!

OpenStudy (mathmusician):

I hope you have a great summer and Thanks for all of the help sir!! God Bless!!

OpenStudy (agent0smith):

You too!

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