Mathematics
4 Online
OpenStudy (mathmusician):
My last math question of the year, Calculus optimization. Help Please!!
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OpenStudy (mathmusician):
@agent0smith can you help with one last question #12 please
OpenStudy (agent0smith):
Set the given equations equal to each other
OpenStudy (mathmusician):
okay
OpenStudy (mathmusician):
\[Me ^{rt}=Ce ^{k \sqrt{t}}\]
OpenStudy (mathmusician):
Do I solve for t again?
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OpenStudy (agent0smith):
"how much money M"
OpenStudy (mathmusician):
so solve for m!
OpenStudy (mathmusician):
okay do i use the given values from previous problems or just keep all of the variables in it
OpenStudy (agent0smith):
They don't say. So... variables.
OpenStudy (mathmusician):
okay
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OpenStudy (mathmusician):
\[M=Ce ^{\sqrt{t}k-tr}\]
OpenStudy (agent0smith):
Yep
OpenStudy (mathmusician):
and that is what i am supposed to compare to topt?
OpenStudy (agent0smith):
Same steps as before, derivative, set to 0 etc
OpenStudy (mathmusician):
okay
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OpenStudy (mathmusician):
I cant derive this, ive been trying
OpenStudy (agent0smith):
If you can derive the one from a while ago, you can do this one.
OpenStudy (mathmusician):
Okay so the derivative of e^f(x) is f'(x)e^f(x)?
OpenStudy (agent0smith):
Yep, use that
OpenStudy (mathmusician):
okay
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OpenStudy (mathmusician):
\[Ce ^{k \sqrt{t}-tr}(\frac{ k }{ 2\sqrt{t} }-r)\]
OpenStudy (mathmusician):
And now set equal to zero and solve for t?
OpenStudy (mathmusician):
Ill do that
OpenStudy (agent0smith):
Looks familiar, huh?
OpenStudy (mathmusician):
yeah it does
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OpenStudy (mathmusician):
is it the same as topt?
OpenStudy (mathmusician):
@agent0smith
OpenStudy (agent0smith):
Yeah when I said it looks familiar, i meant cos it looks exactly the same!
OpenStudy (mathmusician):
yeah haha thanks mate!
OpenStudy (agent0smith):
Welcome mate!
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OpenStudy (mathmusician):
I hope you have a great summer and Thanks for all of the help sir!! God Bless!!
OpenStudy (agent0smith):
You too!