Question

Find the zeros of the polynomial function and state the multiplicity of each.

f(x) = 3(x + 8)2(x - 8)3

Answer 1

3(x + 8)^2(x - 8)^3 = 0

so we can say

(x + 8)^2 = 0 or (x - 8)^3 = 0

Answer 2

if (x + 8)^2 = 0
then x + 8 = 0

so x = ?

Answer 3

Answers:
-8, multiplicity 2; 8, multiplicity 3
4, multiplicity 1; 8, multiplicity 1; -8, multiplicity 1
-8, multiplicity 3; 8, multiplicity 2
4, multiplicity 1; -8, multiplicity 3; 8, multiplicity 3

Answer 4

Ummm 8x?

Answer 5

x + 8 = 0
you need to isolate x so you subtract 8 from both sides

x + 8 - 8 = 0 - 8

so?

Answer 6

the results will be a number not another term in x

Answer 7

x = 8x does not make sense

Answer 8

Yeah..I'm not sure how to do this..sorry

Answer 9

It would equal -8? @welshfella

Answer 10

yes -8 is correct

x + 8 - 8 = 0 - 8 (8 - 8 = 0) so

x = 0-8 = -8


and its multiplicity 2 becaus e of the ^2.

Answer 11

Now you deal with ( x - 8)^3 in exactly the same way

x - 8 = 0

solve for x Multiplicity will be 3

Answer 12

Okay thank makes sense

Answer 13

So then I'd say it's A?

Answer 14

you isolate x this time by adding 6 to both sides

Answer 15

* adding 8

Answer 16

yea

Answer 17

x = 8 for the (x - 8)^3 = 0

Answer 18

Yes, thank you