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Explain the difference between using the cosine ratio to solve for a missing angle in a right triangle versus using the secant ratio. You must use complete sentences and any evidence needed (such as an example) to prove your point of view.
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There is no significant difference. When you know the hypotenuse and another side that's adjacent to the missing angle in a right triangle, you can use 'cosine' or 'secant' ratios. cosθ = adjacent/hypotenuse secθ = 1/cosθ = hypotenuse/adjacent. secant = 1/cos So, there is no difference. Secant is just the reciprocal of cosine. You can use either one of them. There is just a little algebraic manipulation to get from one to the other.
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