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Mathematics 6 Online
zarkam21 (zarkam21):

Helpppp

zarkam21 (zarkam21):

zarkam21 (zarkam21):

This would be 318-42

OpenStudy (agent0smith):

You need that link from the other questions...

zarkam21 (zarkam21):

276/2

zarkam21 (zarkam21):

138

OpenStudy (agent0smith):

Maybe, lol i don't remember without that link.

zarkam21 (zarkam21):

Ugh

OpenStudy (agent0smith):

i think it's right tho

OpenStudy (agent0smith):

I think it was half their difference

zarkam21 (zarkam21):

Sure?

OpenStudy (welshfella):

Join CO and BO this forms a kite BACO the angle at center = small arc = 42 angles SCO and BCO are both 90 degrees because of the 2 tangents so we have <BAC = 360- 2(90) - 42

OpenStudy (agent0smith):

@zarkam21 post that link i gave you earlier in every thread.

zarkam21 (zarkam21):

138

OpenStudy (welshfella):

right

zarkam21 (zarkam21):

This would simply be 360-262

zarkam21 (zarkam21):

OpenStudy (agent0smith):

Lol post that link cos it has all the formulas :P

zarkam21 (zarkam21):

I ust need to know really fast, because I have to submit this

OpenStudy (agent0smith):

lol well post that link, it has the formulas, it's in your old questions

OpenStudy (agent0smith):

http://www.regentsprep.org/regents/math/geometry/gp15/circleangles.htm It's number 3

OpenStudy (sshayer):

|dw:1466107449250:dw|

zarkam21 (zarkam21):

138

OpenStudy (sshayer):

correct reason is the sum of four angles of a quadrilateral=360 here sum of two tangents=180

zarkam21 (zarkam21):

So the final answer is 138

OpenStudy (sshayer):

this is for first question

OpenStudy (sshayer):

|dw:1466123705438:dw|

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