y-5=3/10(x--5)
into standard form that passes through the points (-4, 5) and (6, 2)

Question

y-5=3/10(x--5)
into standard form that passes through the points (-4, 5) and (6, 2)

sshayer · Answer

slope of this line=3/10
slope of line  passing through  (-4,5)and (6,2)
$$=\frac{ 2-5 }{ 6-(-4) }=\frac{ -3 }{ 10 }$$
so two points can not lie on the given line.
They can cut only in one point.

sshayer · Answer

10 y-50=3x-15
10y-3x=35     (1)
eq. of line through two points is 
$$y-5=\frac{ -3 }{ 10 }\left( x-(-4) \right)=\frac{ -3 }{ 10 }\left( x+4 \right)$$
10y-50=-3x-12
10 y+3x=38   (2)
adding (1) and (2)
20 y=73
y=3.65
3x=38-36.5=1.5
x=0.5
so these given point does not lie on the given line.

sshayer · Answer

i think the points should be (4,5)and (6,2)