Question

A fraternity is to elect a president and a treasurer from the group of 40 members. How many ways can these two officers be elected?

Answer 1

The number of ways to elect a president:
\[C \frac{ 1 }{ 40 } = 40\]
\[C= \frac{ 1 }{ 39 } = 39\]
\[Possible Combinations: N=40*39=1560\]
So, two officers can be elected with1560 different ways.

Answer 2

what is C?

Answer 3

https://www.mathsisfun.com/combinatorics/combinations-permutations.html