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in the following drawing find a if b=4 and c=21 round your answer to two decimal places
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\(a^2+b^2=c^2\implies a^2=c^2-b^2\implies a=\pm\sqrt{c^2-b^2}\) But since we are dealing with positive quantity's, we have \[a=\sqrt{c^2-b^2}\]
Can someone answer my question?
that did not show that in my book for the lesson
@templeguy what is your question?
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@zzr0ck3r Here it is...
What was the joke from 19:19 to 19:47 in this vid http://thevideo.me/96qe2nmzox4i
yeah I am not installing things.
@zzr0ck3r you don't have to install anything
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