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@jhonyy9
What's inside the radical ?
Sub u = x-1
You may also try x-1 = u^2
x becomes (x+1), \[\sqrt{x-1}\] becomes \[\sqrt{u}\]
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Sub y = \[\sqrt{u}\]
dy = \[1/2\sqrt{u}\] 2dy = \[1/\sqrt{u}\]
You have \[2\int\limits_{}^{}dy/(y ^{2}+1)\] The rest is standard integration.
oh okay :) got it :D
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