Question

Rewrite the following quadratic function in vertex form. Then, determine the axis of symmetry.

y = 5x^2 + 15x - 2

Answer 1

\[y=5x ^{2}+15x-2\]
\[y=5(x^2+3)-2\]
\[(3/2)^2=9/4\]
\[y=5(x+1.5)^2-2-(9/4)\]

Answer 2

inside parantheses next 3 you missed an x cosmo !

Answer 3

@Cosmo ATTENTION !!!

Answer 4

y=5x2+15x−2
y=5(x2+3x)−2
(3/2)2=9/4
y=5(x+1.5)2−2−(9/4)