Solve −2x^2 +3x − 9 = 0

Question

prince1342 · Answer

x equals quantity of 3 plus or minus 3i square root of 7 all over 4
 x equals quantity of 3 plus or minus 9i square root of 7 all over 4
 x equals quantity of negative 3 plus or minus 3i square root of 7 all over 4
 x equals quantity of negative 3 plus or minus 9i square root of 7 all over 4

koikkara · Answer

well, can u please say how it looks like.... to you ?

prince1342 · Answer

what do you mean?

koikkara · Answer

you can use  your textbook  and say what quadratic form it is in....

prince1342 · Answer

its in standard form

koikkara · Answer

click this > http://www.tiger-algebra.com/drill/2x~2_3x-9=0/

prince1342 · Answer

x=−b±b2−4ac√2awhenax2+bx+c=0

koikkara · Answer

go through the link, it will help u understand.

koikkara · Answer

did u get... anything like...

2x^2 + 3x - 9 = 0 
2x^2 - 3x + 9 = 0 
x = [3 ± √((-3)^2 - 4 * 2 * 9)] / (2 * 2) 
x = (3 ± √-63) / 4 
x = (3 ± 3i√7) / 4

prince1342 · Answer

no i got nothing like my answer choices