Question

Can someone please help me on this math question? please? I'll fan and give a medal!!

Answer 1

For questions 17 through 20 use f(x) = x2 – x + 2
17. find f(2)

Answer 2

@Abbles

Answer 3

would it be f(x) = x2 – x + 2
---
f(2) = (2)2 – (2) + 2
or --
f(2) = x2 – (2) + 2
?

Answer 4

Assuming x2 means x squared, it would look like:
f(2) = 2^2 - 2 + 2
So you're first one looks about right :)

Answer 5

okay I'll do that, but the question didn't have x^2 just x2

Answer 6

My teacher might have forgotten to square it... I guess

Answer 7

just plug x=2 and find the solution.

Answer 8

can you show me the solution?

Answer 9

\[f(x)=x^2-x+2\]
\[f(2)=2^2-2+2=?\]

Answer 10

If it is indeed squared, the solution would be:
f(2) = 2^2 - 2 + 2
f(2) = 4 - 2 + 2
f(2) = 4

Answer 11

Unless the 2 is actually before the x on the first term? In which case it would be:
f(2) = 2(2) - 2 + 2
f(2) = 4 - 2 + 2
f(2) = 4

Which actually turns out to be the same thing!

Answer 12

correct.

Answer 13

@Abbles Thank you!!!! You don't know how much I appreciate your help!

Answer 14

no, when written x2-x+2
it is \[x^2-x+2\]
when written 2x-x+2
it is 2*x-x+2

Answer 15

Your welcome :) ask away if you have any more Qs, I'm happy to help.

Answer 16

Could you check this answer? please?

18. Find f(0)
f(0)= 0^2 – 0 + 2
f(0)= 0 – 0 +2
f(0)=2

Answer 17

correct.

Answer 18

f(x) = x^2 – x + 2
19. Find f(-4)
f(-4)= -4^2 – (-4) + 2
f(-4)= -16-(-4)+2
f(-4)= -12+2
f(-4)= -10

Answer 19

Your f(0) is correct but not the f(4).

Answer 20

What is -4 times -4?

Answer 21

correction
\[f(-4)=(-4)^2-(-4)+2=?\]

Answer 22

would it be 16?

Answer 23

Yes.
f(x) = x^2 – x + 2
f(-4)=( -4)^2 – (-4) + 2
f(-4)= 16 + 4 +2
f(-4)= 22

Answer 24

Thank you!! Could you check this last problem? Please?
f(x) = x^2 – x + 2
20. Find f(1)
f(1)= 1^2 – 1 + 2
f(1)=1-1+2
f(1)=2

Answer 25

Sure thing.
Looks all good :)

Answer 26

Great! thank you for everything!! You're awesome!! :)