Question

Solve the triangle.

A = 19°, C = 102°, c = 6

Answer 1

@mathstudent55

Answer 2

First find angle B ..... sum of triangle is 180

Answer 3

Then use Law of Sines twice to find sides a and b

\[\frac{a}{\sin A} = \frac{c}{\sin C}\]

Answer 4

\[\frac{b}{\sin B} = \frac{c}{\sin C}\]