Question

help

Answer 1

Solve the compound inequality 6b < 42 or 4b + 12 > 8.

b < 6 or b > 5
b < 7 or b > −1
b < 7 or b > 1
b > 6 or b < 5

Answer 2

is it B.

Answer 3

@Data_Lg2
@Mehek14
@zepdrix

Answer 4

Yes, you are correct.

Answer 5

Can you help with some more?

Answer 6

Yes

Answer 7

Solve and graph the absolute value inequality: |2x + 4| > 8.

number line with open circles on negative 6 and 2, shading in between.
number line with closed circles on negative 6 and 2, shading going in the opposite directions.
number line with open circles on negative 6 and 2, shading going in the opposite directions.
number line with open circles on negative 2 and 2, shading going in the opposite directions.

Answer 8

I'm not sure what the answer is.

Answer 9

Do you have images of the number lines?

Answer 10

no

Answer 11

Rule:
`|x| > k` will break into `x > k` or `x < -k` where k is some positive number

Answer 12

Using the rule, this will make
|2x + 4| > 8
turn into
2x+4 > 8 or 2x+4 < -8

solve the two inequalities for x

Answer 13

x=2 and x=-24?

Answer 14

wait

Answer 15

x=greater than 2 and x= less than -24?

Answer 16

2x+4 > 8
2x+4-4 > 8-4
2x > 4
2x/2 > 4/2
x > 2
first part looks good

Answer 17

2x+4 < -8
2x+4-4 < -8-4
2x < -12
2x/2 < -12/2
x < -6

Answer 18

you must have doubled 12 to get 24, when you should have divided both sides by 2 instead

Answer 19

oh

Answer 20

Solve and graph the absolute value inequality: |2x + 4| > 8.

number line with open circles on negative 6 and 2, shading in between.
number line with closed circles on negative 6 and 2, shading going in the opposite directions.
number line with open circles on negative 6 and 2, shading going in the opposite directions.
number line with open circles on negative 2 and 2, shading going in the opposite directions.
is it c

Answer 21

so we found that x > 2 or x < -6. Do you know how to graph this on a number line?

Answer 22

open circle on -6 going to the left and open circle on 2 going to the right.

Answer 23

very good

Answer 24

thanks

Answer 25

no problem