Question

7x^2-19x-6

Answer 1

what is the question?

Answer 2

$$\large (px+r)(qx+s)$$
Since the leading coefficient of 7 is prime p =7 and q =1
$$\large (7x+r)(x+s)$$
now, since -6 is negative r and s will have opposite signs.

Answer 3

recall: the order of the factors is important
r, s
1, -6
2, -3
3, -2
6, -1
-1, 6
-2, 3
-3, 2
-6, 1

Answer 4

Test these^ possibilities to see which produces the correct linear term, namely -19x.

Answer 5

7*-6=-42
21-2=19
21*-2=-42
\[7x^2-\left( 21-2 \right)x-6=7x^2-21x+2x-6=7x(x-3)+2(x-3)=?\]