The following table shows the data of a random sample of fish collected from and later released into a lake:

Type of Fish Bass Catfish Warmouth
Number of fish 60 70 20

How many bass are estimated to be present if a random sample of 1,500 fish is collected from the lake?

130
600
750
900

Question

The following table shows the data of a random sample of fish collected from and later released into a lake:

Type of Fish	Bass	    Catfish	   Warmouth
Number of fish	 60	      70	       20


How many bass are estimated to be present if a random sample of 1,500 fish is collected from the lake?

130
600
750
900

jim_thompson5910 · Answer

estimated number of bass = [(# of recorded bass)/(previous total)]*(new total)

nikki_skellington · Answer

what do you mean by previous total and new total????

jim_thompson5910 · Answer

in the first sample, the total is 60+70+20 = 150. I'm referring to this as the "previous total"

In the next sample, the total jumps to 1500 which I call the "new total"

nikki_skellington · Answer

ok got it so 60/150 times 1,500

jim_thompson5910 · Answer

correct

nikki_skellington · Answer

which is...hold on give me a sec plz

nikki_skellington · Answer

600 right?

jim_thompson5910 · Answer

correct

nikki_skellington · Answer

ok thank you so much!

jim_thompson5910 · Answer

np