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Find the range of the function. f(x) = (x - 2)^2 + 2
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Answer Choices: All real numbers y ≥ 0 y < 2 y ≥ 2
for the range you need to think about least value the function f(x) can take
I think it's y is greater than or equal to 2
because 2 is the smallest possible value
yes it is
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if it was 0 you would have 0=(x-2)^2+2 realize that this cannot happen
range is the lowest y value ( negative ) to highest positive y values
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