Question

In the figure, if m∠ABD = 120º, then m∠ADC = ?

Answer 1

@anthonyym

Answer 2

@welshfella

Answer 3

first find <ADB using the sine rule

Answer 4

then <ADC = 180 - <ADB

Answer 5

Hi sorry I was away.
What @welshfella said is right you find <ADB using the law of sine \[\sin(\angle ADB)=\frac{ AB }{ AD }\sin(\angle ABD)\] Then you find its complementary.

Answer 6

thanks!!

Answer 7

Anytime !