Question

What values of x and y satisfy −13/3x−2y=7 and 3x+2/5y=5 simultaneously

Answer 1

one approach
multiply by the LCD to get rid of the fractions
put each in the form y =
set the y's equal and solve for x
substitute this value in the expression to compute the value of y

Answer 2

-13/3x - 2y = 7...multiply by 3 to get rid of fractions
3x + 2/5y = 5...multiply by 5 to get rid of fractions

-13x - 6y = 21
15x + 2y = 25...multiply by 3
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-13x - 6y = 21
45x - 6y = 75 (result of multiplying by 3)
------------add
32x = 96
x = 96/32
x = 3

15x + 2y = 25
15(3) + 2y = 25
45 + 2y = 25
2y = 25 - 45
2y = - 20
y = -10

solution is : (3,-10)