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Solve this equation by completing the square. 3x^2 - 4x = -2
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no direct answers. guide the asker to the correct solution.
no i was just....uh.....sorry ;-;
for a quadratic you get two solutions.
remember this (a-b)^2 = a^2 -2ab + b^2
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im not really sure sorry :(
3x^2 - 4x = -2 3[ x^2 - (4/3)x] = -2 3[ (x - 2/3 x)^2 - 4/9] = -2 (x - 2/3 x)^2 - 4/9] = -2/3 (x - 2/3 x)^2 = -2/3 + 4/9 = - 2/9
No real roots 2 complex roots
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