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Trigonometry
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cos theta -cos theta sin^2 theta. I know the answer is cos ^3 theta but i'm not sure how i got the answer
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\[\cos\theta-\cos\theta\sin^2\theta=\cos\theta\left(1-\sin^2\theta\right)\]If it's unclear what happened there, think of the left hand side as \[a-ab^2=a(1-b^2)\] Now, what do you know about \(1-\sin^2\theta\)?
1 - sin^2 theta = cos^2 theta
cos cos theta ( 1 - sin^2 theta) = cos^3 theta
- ignore the first cos!!
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